A、n=int(input())result=0foriinrange(n):ifi%2==1:result=result+iprint(result)
B、n = int(input())result = 0for i in range(1, n):if i % 2 == 1:result = result + iprint(result)
C、n = int(input())result = 0for i in range(n):result = result + iprint(result)
D、n = int(input())print(sum([i for i in range(n) if i % 2 == 1]))
答案:ABD
A、n=int(input())result=0foriinrange(n):ifi%2==1:result=result+iprint(result)
B、n = int(input())result = 0for i in range(1, n):if i % 2 == 1:result = result + iprint(result)
C、n = int(input())result = 0for i in range(n):result = result + iprint(result)
D、n = int(input())print(sum([i for i in range(n) if i % 2 == 1]))
答案:ABD
A. s
D. ata
E. ad()csv('1.csv')(1)
F. rame,按照要求编写代码:import pandas as pddf = pd.read()csv('1.csv')(1) 输出df的末10行;(2) 输出df的前5行;(3) 输出df的前4行前5列的内容;我的
A. 对
B. 错
A. frame[frame('age') > 17 & frame('height) > 1.80]
B. frame[(frame('age') > 17) & (frame('height) > 1.80)]
C. frame[(frame['age'] > 17) & (frame['height] > 1.80)]
D. frame[[frame('age') > 17] & [frame('height) > 1.80]]
A. sort()是原地排序,无返回值
B. sorted()返回一个排序的列表
C. 二者都可以用参数key指定排序关键字
D. 二者默认都是升序排序
解析:答案解析:
A. ()
B. (1)
C. 1,
D. (1,2,3,4)
A. Letter[-1:-4:-1]
B. Letter( :3:2)
C. Letter[1:3:0]
D. Letter[ 'a': 'd': 2]
A. Letter[-1:-4:-1]
B. Letter( :3:2)
C. Letter[1:3:0]
D. Letter[ 'a': 'd': 2]